document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=323122>Question 323122</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Brianna has an alloy containing 10% gold. Emma has 1/2 ounces of an alloy<BR>\n" );
document.write( "containing 71% gold. They combined their alloys to make an alloy with 46 3/5% gold. Gold is worth $209.31 an ounce at the current market value. Brianna estimated the value of the new alloy to be $81.28 an ounce. How many ounces of Brianna's alloy were used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231312 by </B><A HREF=/tutors/aboutme.mpl?userid=galactus><B>galactus(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galactus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=galactus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of alloy Brianna is using.\r<BR>\n" );
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document.write( "The amount of gold is then\r<BR>\n" );
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document.write( ".10x+.71(.5)=.466(.5+x)\r<BR>\n" );
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document.write( "Solve for x to find how much alloy Brianna used.\r<BR>\n" );
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document.write( "Since .10x+.71(.5) is the amount of gold in the alloys, plugging this value into .10x+.71(.5) and multiplying by 209.31 should give 81.28.   </SPAN>\n" );
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