document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=323083>Question 323083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles form a linear pair.  The measure of one angle is seven less than twice the measure of the other angle.  what are the measures of both the angles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231295 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles form a linear pair. <BR>\n" );
document.write( "x + y = 180<BR>\n" );
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document.write( "The measure of one angle is seven less than twice the measure of the other angle. <BR>\n" );
document.write( "x = 2y-7<BR>\n" );
document.write( "---------------------\r<BR>\n" );
document.write( "\n" );
document.write( "what are the measures of both the angles?<BR>\n" );
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document.write( "Substitute for \"x\" and solve for \"y\":<BR>\n" );
document.write( "2y-7 + y = 180<BR>\n" );
document.write( "3y = 187<BR>\n" );
document.write( "y = 62 1/3<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Since x+y = 180, x = 180-62 1/3 = 117 2/3<BR>\n" );
document.write( "=======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );