document.write( "Question 323053: One number is 3 less than another. If 4 times the smaller number minus 3 times the larger number is 4, find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #231289 by ankor@dixie-net.com(22740)\"\" \"About 
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let x = \"One number\"
\n" ); document.write( "let y = \"another number\"
\n" ); document.write( ":
\n" ); document.write( "One number is 3 less than another.
\n" ); document.write( "x = y - 3
\n" ); document.write( ":
\n" ); document.write( "If 4 times the smaller number minus 3 times the larger number is 4,
\n" ); document.write( "4x - 3y = 4
\n" ); document.write( ":
\n" ); document.write( "find the two numbers.
\n" ); document.write( "Replace x with (y-3)
\n" ); document.write( "4(y-3) - 3y = 4
\n" ); document.write( "4y - 12 - 3y = 4
\n" ); document.write( "4y - 3y = 4 + 12
\n" ); document.write( "y = 16
\n" ); document.write( ":
\n" ); document.write( "I'll let you find x
\n" ); document.write( "
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