document.write( "Question 323053: One number is 3 less than another. If 4 times the smaller number minus 3 times the larger number is 4, find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #231289 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let x = \"One number\" \n" ); document.write( "let y = \"another number\" \n" ); document.write( ": \n" ); document.write( "One number is 3 less than another. \n" ); document.write( "x = y - 3 \n" ); document.write( ": \n" ); document.write( "If 4 times the smaller number minus 3 times the larger number is 4, \n" ); document.write( "4x - 3y = 4 \n" ); document.write( ": \n" ); document.write( "find the two numbers. \n" ); document.write( "Replace x with (y-3) \n" ); document.write( "4(y-3) - 3y = 4 \n" ); document.write( "4y - 12 - 3y = 4 \n" ); document.write( "4y - 3y = 4 + 12 \n" ); document.write( "y = 16 \n" ); document.write( ": \n" ); document.write( "I'll let you find x \n" ); document.write( " |