document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=323062>Question 323062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Things did not go quite as planned. You invested part of $8000 in an account that paid 12% annual interest. However the rest of the money suffered a 5%loss. If the total annual income from both investments was $620 how much was invested in each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231264 by </B><A HREF=/tutors/aboutme.mpl?userid=galactus><B>galactus(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galactus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=galactus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount invested at 12%.\r<BR>\n" );
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document.write( "Then, the remaining amount invested at 5% must be 8000-x\r<BR>\n" );
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document.write( ".12x-.05(8000-x)=620\r<BR>\n" );
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document.write( "Solve for x.  </SPAN>\n" );
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