document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37526>Question 37526</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sally bought three chocolate bars and a pack of gum and paid $1.75. Jake bought two chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23126 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let C be the number of chocolate bars.<BR>\n" );
document.write( "Let G be the number of packs of gum.<BR>\n" );
document.write( "Then we have two algebra sentences involving C and G:<BR>\n" );
document.write( "3C + G = 1.75<BR>\n" );
document.write( "2C + 4G = 2.00<BR>\n" );
document.write( "We can solve the first equation for G and substitute its value into the second equation...<BR>\n" );
document.write( "G = -3C + 1.75<BR>\n" );
document.write( "2C + 4(-3C + 1.75) = 2.00<BR>\n" );
document.write( "2C - 12C + 7 = 2.00<BR>\n" );
document.write( "-10C = -5<BR>\n" );
document.write( "C = .50<BR>\n" );
document.write( "and if C = .50, then<BR>\n" );
document.write( "G = -3(.50) + 1.75<BR>\n" );
document.write( "G = -1.50 + 1.75<BR>\n" );
document.write( "G = .25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );