document.write( "Question 323010: 3r-5s=21
\n" ); document.write( "5r+3s=33
\n" ); document.write( "solve by elimination method
\n" ); document.write( "

Algebra.Com's Answer #231241 by stanbon(75887)\"\" \"About 
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3r-5s=21
\n" ); document.write( "5r+3s=33
\n" ); document.write( "solve by elimination method
\n" ); document.write( "-------------------
\n" ); document.write( "Multiply 1st by 5
\n" ); document.write( "Multiply 2nd by 3
\n" ); document.write( "-----------
\n" ); document.write( "15r - 25s = 105
\n" ); document.write( "15r + 9s = 99
\n" ); document.write( "-----
\n" ); document.write( "Subtract 1st from 2nd to get:
\n" ); document.write( "34s = -6
\n" ); document.write( "s = -3/17
\n" ); document.write( "==================
\n" ); document.write( "Substitute into 3r-5s = 21 to solve for r:
\n" ); document.write( "3r -5(-3/17) = 21
\n" ); document.write( "3r = 21 -15/17
\n" ); document.write( "r = 7 - 5/17
\n" ); document.write( "r = 114/17
\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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