document.write( "Question 323010: 3r-5s=21
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document.write( "5r+3s=33
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document.write( "solve by elimination method \n" );
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Algebra.Com's Answer #231241 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3r-5s=21 \n" ); document.write( "5r+3s=33 \n" ); document.write( "solve by elimination method \n" ); document.write( "------------------- \n" ); document.write( "Multiply 1st by 5 \n" ); document.write( "Multiply 2nd by 3 \n" ); document.write( "----------- \n" ); document.write( "15r - 25s = 105 \n" ); document.write( "15r + 9s = 99 \n" ); document.write( "----- \n" ); document.write( "Subtract 1st from 2nd to get: \n" ); document.write( "34s = -6 \n" ); document.write( "s = -3/17 \n" ); document.write( "================== \n" ); document.write( "Substitute into 3r-5s = 21 to solve for r: \n" ); document.write( "3r -5(-3/17) = 21 \n" ); document.write( "3r = 21 -15/17 \n" ); document.write( "r = 7 - 5/17 \n" ); document.write( "r = 114/17 \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |