document.write( "Question 323021: how do I solve for x\r
\n" ); document.write( "\n" ); document.write( "1x + 2y<= 20\r
\n" ); document.write( "\n" ); document.write( "Well how do I get the x by itself.
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Algebra.Com's Answer #231224 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"1x+%2B+2y%3C=+20\"$
\n" ); document.write( " $\"x%3C20-2y\"$ <--- Subtract 2y from both sides. \n" ); document.write( "

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