document.write( "Question 322989: please help...i tried to work the problem with the formula given
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document.write( "z=value-mean/standard deviation
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document.write( "According to a survey conducted by television advertisers, the average adult American watches an average of 6.98 hours of television per day. The data is normally distributed with a standard devieation of 3.80 hours. Find the probability that a randomly selected person watches more than 8.00 hours of television a day.
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document.write( "8.00-6.98/3.80=6.163...is this correct? \n" );
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Algebra.Com's Answer #231191 by stanbon(75887) ![]() You can put this solution on YOUR website! work the problem with the formula given \n" ); document.write( "z=value-mean/standard deviation \n" ); document.write( "According to a survey conducted by television advertisers, the average adult American watches an average of 6.98 hours of television per day. The data is normally distributed with a standard devieation of 3.80 hours. Find the probability that a randomly selected person watches more than 8.00 hours of television a day. \n" ); document.write( "8.00-6.98/3.80=6.163...is this correct? \n" ); document.write( "--------------------- \n" ); document.write( "Note: Your Formula is wrong; you always need parentheses in the numerator. \n" ); document.write( "It should be z-value = (value-mean)/standard deviation \n" ); document.write( "----- \n" ); document.write( "z(8) = (8-6.93)/3.8 = 1.02/3.8 = 0.2684 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |