document.write( "Question 322987: A car and a bus leave town at 1 P.M. and head for a town 300 mi away. The rate of the car is twice the rate of the bus. The car arrives 5 h ahead of the bus. Find the rate of the car. \n" ); document.write( "
Algebra.Com's Answer #231189 by stanbon(75887)\"\" \"About 
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A car and a bus leave town at 1 P.M. and head for a town 300 mi away. The rate of the car is twice the rate of the bus. The car arrives 5 h ahead of the bus. Find the rate of the car.
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\n" ); document.write( "Car DATA:
\n" ); document.write( "distance = 300 mi ; rate = 2x mph ; time = d/r = 300/(2x) hrs
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\n" ); document.write( "Bus DATA:
\n" ); document.write( "distance = 300 mi ; rate = x mph ; time = d/r = 300/x hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "Bus time - Car time = 5 hrs.
\n" ); document.write( "300/x - 300/(2x) = 5
\n" ); document.write( "600 - 300 = 10x
\n" ); document.write( "10x = 300
\n" ); document.write( "x = 30 mph
\n" ); document.write( "2x = 60 mph (rate of the car)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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