document.write( "Question 322987: A car and a bus leave town at 1 P.M. and head for a town 300 mi away. The rate of the car is twice the rate of the bus. The car arrives 5 h ahead of the bus. Find the rate of the car. \n" ); document.write( "
Algebra.Com's Answer #231189 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A car and a bus leave town at 1 P.M. and head for a town 300 mi away. The rate of the car is twice the rate of the bus. The car arrives 5 h ahead of the bus. Find the rate of the car. \n" ); document.write( "--- \n" ); document.write( "Car DATA: \n" ); document.write( "distance = 300 mi ; rate = 2x mph ; time = d/r = 300/(2x) hrs \n" ); document.write( "------------- \n" ); document.write( "Bus DATA: \n" ); document.write( "distance = 300 mi ; rate = x mph ; time = d/r = 300/x hrs \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "Bus time - Car time = 5 hrs. \n" ); document.write( "300/x - 300/(2x) = 5 \n" ); document.write( "600 - 300 = 10x \n" ); document.write( "10x = 300 \n" ); document.write( "x = 30 mph \n" ); document.write( "2x = 60 mph (rate of the car) \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |