document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322915>Question 322915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A company's new printer can print checks three times faster than its old printer.<BR>\n" );
document.write( "with both printers operating ,the checks can be printed in 6 minutes. how long would it take to print the checks with the new printer only ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231160 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the old printer's speed be x checks <BR>\n" );
document.write( "1/x of the check it does it 1 minute<BR>\n" );
document.write( "..<BR>\n" );
document.write( "new printer will print at 3x checks <BR>\n" );
document.write( "1/3x checks it prints in 1 minute<BR>\n" );
document.write( "..<BR>\n" );
document.write( "both print in 6 minutes<BR>\n" );
document.write( "So 1/6 of the job they do in 1 minute<BR>\n" );
document.write( "..<BR>\n" );
document.write( "1/x + 1/3x = 1/6<BR>\n" );
document.write( "3+1 /3x= 1/6<BR>\n" );
document.write( "6*4=3x<BR>\n" );
document.write( "3x=24 <BR>\n" );
document.write( "x= 8 checks by the old printer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );