document.write( "Question 322878: The sum of twice a first number and five times a second number is 111. If the second number is subtracted from five times the first number the result is 21. Find the numbers \n" ); document.write( "
Algebra.Com's Answer #231142 by mananth(16946)\"\" \"About 
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The sum of twice a first number and five times a second number is 111.
\n" ); document.write( "let one number be x: other number be y
\n" ); document.write( "2x+5y=111................ equation 1
\n" ); document.write( "..\r
\n" ); document.write( "\n" ); document.write( "the second number is subtracted from five times the first number the result is 21.
\n" ); document.write( "5x-y=21................... equation 2\r
\n" ); document.write( "\n" ); document.write( "multiply equation 2 by 5 and it to equation 1 to eliminate y
\n" ); document.write( "25x-5y=105
\n" ); document.write( "..
\n" ); document.write( "25x-5y+2x+5y=105+111
\n" ); document.write( "27x=216
\n" ); document.write( "x=8
\n" ); document.write( "..
\n" ); document.write( "plug the value of x in equation 2
\n" ); document.write( "40-y=21
\n" ); document.write( "-y=-19
\n" ); document.write( "y=19
\n" ); document.write( "..
\n" ); document.write( "The numbers are 8 & 19
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