document.write( "Question 322878: The sum of twice a first number and five times a second number is 111. If the second number is subtracted from five times the first number the result is 21. Find the numbers \n" ); document.write( "
Algebra.Com's Answer #231142 by mananth(16946)![]() ![]() You can put this solution on YOUR website! The sum of twice a first number and five times a second number is 111. \n" ); document.write( "let one number be x: other number be y \n" ); document.write( "2x+5y=111................ equation 1 \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "the second number is subtracted from five times the first number the result is 21. \n" ); document.write( "5x-y=21................... equation 2\r \n" ); document.write( "\n" ); document.write( "multiply equation 2 by 5 and it to equation 1 to eliminate y \n" ); document.write( "25x-5y=105 \n" ); document.write( ".. \n" ); document.write( "25x-5y+2x+5y=105+111 \n" ); document.write( "27x=216 \n" ); document.write( "x=8 \n" ); document.write( ".. \n" ); document.write( "plug the value of x in equation 2 \n" ); document.write( "40-y=21 \n" ); document.write( "-y=-19 \n" ); document.write( "y=19 \n" ); document.write( ".. \n" ); document.write( "The numbers are 8 & 19 \n" ); document.write( " |