document.write( "Question 322855: The length of a rectangle is 7 m less than 4 time the width. the perimeter is 136 m. Find the width and lenght. \n" ); document.write( "
Algebra.Com's Answer #231140 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x=width
\n" ); document.write( "4x-7 = length\r
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\n" ); document.write( "\n" ); document.write( "2(x)+2(4x-7)=136
\n" ); document.write( "2x+8x-14=136
\n" ); document.write( "10x=150
\n" ); document.write( "x=15 = width\r
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\n" ); document.write( "\n" ); document.write( "4x-7= length
\n" ); document.write( "4(15) -7=60-7=53 = Length\r
\n" ); document.write( "\n" ); document.write( "Check: 2*15 + 2*53
\n" ); document.write( "30+106=136
\n" ); document.write( "It checks!\r
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\n" ); document.write( "\n" ); document.write( "For additional help with square roots, please see my own website. Click on my tutor name \"rapaljer\" anywhere in algebra.com. There, click on my website. From my Homepage, look for the link near the top of the page \"Basic, Intermediate, and College Algebra: One Step at a Time.\" Then click on \"Basic Algebra\", then \"Chapter 1\", \"Sections 1.09 and 1.10.\" There you will find my own non-traditional explanations, examples, exercises, and answers to ALL the exercises, and solutions to many of the problems on the \"MATH IN LIVING COLOR\" pages that go with these explanations.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
\n" ); document.write( "Seminole State College of Florida
\n" ); document.write( "Altamonte Springs Campus
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