document.write( "Question 322824: A chemist has one solution that is 80% acid and a second solution that is 44% acid. She wants to combine the solutions to make a new solution that is 53% acid. If she needs to make 320 Milliliters of this new solution, how many milliliters of the two solutions should be mixed? \n" ); document.write( "
Algebra.Com's Answer #231133 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 80% solution, B the amount of 44% solution.
\n" ); document.write( "1.\"A%2BB=320\"
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\n" ); document.write( "\"80A%2B44B=53%28320%29\"
\n" ); document.write( "2.\"20A%2B11B=4240\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"A=320-B\"
\n" ); document.write( "\"20A=6400-20B\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"6400-20B%2B11B=4240\"
\n" ); document.write( "\"-9B=-2160\"
\n" ); document.write( "\"B=240\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A%2B240=320\"
\n" ); document.write( "\"A=80\"
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\n" ); document.write( "80 ml of 80% solution and 240 ml of 44% solution.
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