document.write( "Question 322751: A rectangular field is to be enclosed by a fence and then divded into two small plots by a fence parallel to one of the sides. If thre is 1800 m of fencing available, find the dimensions of the field that will give the maximum area. \n" ); document.write( "
Algebra.Com's Answer #231104 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular field is to be enclosed by a fence and Ithen divided into two
\n" ); document.write( " small plots by a fence parallel to one of the sides.
\n" ); document.write( "If there is 1800 m of fencing available, find the dimensions of the field that will give the maximum area.
\n" ); document.write( ":
\n" ); document.write( "2L + 3W = 1800
\n" ); document.write( "2L = 1800-3W
\n" ); document.write( "Divide both sides by 2
\n" ); document.write( "L = (900-1.5W)
\n" ); document.write( ":
\n" ); document.write( "Area = L * W
\n" ); document.write( "Replace L with (900-1.5W)
\n" ); document.write( "A = W(900-1.5W)
\n" ); document.write( "A = -1.5W^2 + 900W
\n" ); document.write( "Find the axis of symmetry, x=-b/(2a); in this equation: a=-1.5, b=900
\n" ); document.write( "W = \"%28-900%29%2F%282%2A-1.5%29\"
\n" ); document.write( "W = \"%28-900%29%2F%28-3%29\"
\n" ); document.write( "W = +300 m is the width for max area
\n" ); document.write( "then
\n" ); document.write( "L = 900 - 1.5(300)
\n" ); document.write( "L = 450 m is the length
\n" ); document.write( "and
\n" ); document.write( "300 * 450 = 135,000 sq/m is max area
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