document.write( "Question 322751: A rectangular field is to be enclosed by a fence and then divded into two small plots by a fence parallel to one of the sides. If thre is 1800 m of fencing available, find the dimensions of the field that will give the maximum area. \n" ); document.write( "
Algebra.Com's Answer #231104 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A rectangular field is to be enclosed by a fence and Ithen divided into two \n" ); document.write( " small plots by a fence parallel to one of the sides. \n" ); document.write( "If there is 1800 m of fencing available, find the dimensions of the field that will give the maximum area. \n" ); document.write( ": \n" ); document.write( "2L + 3W = 1800 \n" ); document.write( "2L = 1800-3W \n" ); document.write( "Divide both sides by 2 \n" ); document.write( "L = (900-1.5W) \n" ); document.write( ": \n" ); document.write( "Area = L * W \n" ); document.write( "Replace L with (900-1.5W) \n" ); document.write( "A = W(900-1.5W) \n" ); document.write( "A = -1.5W^2 + 900W \n" ); document.write( "Find the axis of symmetry, x=-b/(2a); in this equation: a=-1.5, b=900 \n" ); document.write( "W = \n" ); document.write( "W = \n" ); document.write( "W = +300 m is the width for max area \n" ); document.write( "then \n" ); document.write( "L = 900 - 1.5(300) \n" ); document.write( "L = 450 m is the length \n" ); document.write( "and \n" ); document.write( "300 * 450 = 135,000 sq/m is max area \n" ); document.write( " |