document.write( "Question 322840: find distance between P and Q
\n" ); document.write( "P( 4,9); Q(9, 21)
\n" ); document.write( "P(6,-3); Q(-3, 2)
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Algebra.Com's Answer #231103 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started.\r
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\n" ); document.write( "\n" ); document.write( "# 1\r
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=4\" and \"y%5B1%5D=9\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=9\" and \"y%5B2%5D=21\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%284-9%29%5E2%2B%289-21%29%5E2%29\" Plug in \"x%5B1%5D=4\", \"x%5B2%5D=9\", \"y%5B1%5D=9\", and \"y%5B2%5D=21\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-5%29%5E2%2B%289-21%29%5E2%29\" Subtract \"9\" from \"4\" to get \"-5\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-5%29%5E2%2B%28-12%29%5E2%29\" Subtract \"21\" from \"9\" to get \"-12\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2825%2B%28-12%29%5E2%29\" Square \"-5\" to get \"25\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2825%2B144%29\" Square \"-12\" to get \"144\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28169%29\" Add \"25\" to \"144\" to get \"169\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=13\" Take the square root of \"169\" to get \"13\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=13\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points P and Q is 13 units.
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