document.write( "Question 322627: why is it that in diff places you do not reciprocate the values that you need to eliminate?for example 1x+2y=3
\n" ); document.write( " 2x+1y=3 then if youre trying to eliminate y or get it it becomes 1(1x+2y=3)
\n" ); document.write( " 2(2x+1y=3)then becomes x+2=3
\n" ); document.write( " 4x+2y=6
\n" ); document.write( "

Algebra.Com's Answer #231077 by ankor@dixie-net.com(22740)\"\" \"About 
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why is it that in diff places you do not reciprocate the values that you need to eliminate?for example 1x+2y=3
\n" ); document.write( "2x+1y=3 then if youre trying to eliminate y or get it it becomes 1(1x+2y=3)
\n" ); document.write( "2(2x+1y=3)then becomes x+2=3
\n" ); document.write( "4x+2y=6
\n" ); document.write( ":
\n" ); document.write( "I am not sure what you are trying to say here,
\n" ); document.write( " but if you want to solve the following by eliminating y:
\n" ); document.write( ":
\n" ); document.write( "1x + 2y = 3
\n" ); document.write( "2x + 1y = 3
\n" ); document.write( "Multiply the 2nd equation by 2 and you have
\n" ); document.write( "1x + 2y = 3
\n" ); document.write( "4x + 2y = 6
\n" ); document.write( "-------------subtracting eliminates y, find x
\n" ); document.write( "-3x = -3
\n" ); document.write( "x = \"%28-3%29%2F%28-3%29\"
\n" ); document.write( "x = +1
\n" ); document.write( ":
\n" ); document.write( "Find y using the 1st equation
\n" ); document.write( "1 + 2y = 3
\n" ); document.write( "2y = 3 - 1
\n" ); document.write( "2y = 2
\n" ); document.write( "y = \"2%2F2\"
\n" ); document.write( "y = +1
\n" ); document.write( ":
\n" ); document.write( "Check solution in the 2nd original equation
\n" ); document.write( "2(1) + 1 = 3
\n" ); document.write( "
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