document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322735>Question 322735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help! Bags of Flour • The weights of bags of flour are normally distributed, with a mean of 5 pounds (80 ounces) and a standard deviation of 0.5 ounce.  Determine an interval of values into which (a) about 95% of the bags of flour will fall and (b) about 68% of the bags of flour will fall.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231024 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It appears you are working a problem associated<BR>\n" );
document.write( "with Chebyshev's Theorem.  If that is true the<BR>\n" );
document.write( "following procedure applies:<BR>\n" );
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document.write( " please help! Bags of Flour • The weights of bags of flour are normally distributed, with a mean of 5 pounds (80 ounces) and a standard deviation of 0.5 ounce. Determine an interval of values into which \r<BR>\n" );
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document.write( "(a) about 95% of the bags of flour will fall and <BR>\n" );
document.write( "According to Chebyshev, 95% of the data lies within 2 standard <BR>\n" );
document.write( "deviations of the mean.  For your problem that would be <BR>\n" );
document.write( "80-2(0.5) oz up to 80+2(0.5) oz<BR>\n" );
document.write( "79 oz to 81 oz<BR>\n" );
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document.write( "(b) about 68% of the bags of flour will fall.<BR>\n" );
document.write( "According to Chebyshev, 68% of the data lies within 1 standard<BR>\n" );
document.write( "deviation of the mean. For your problem that would be <BR>\n" );
document.write( "80-0.5 up to 80+0.5<BR>\n" );
document.write( "79.5 oz up to 80.5 oz<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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