document.write( "Question 322743: Please help me figure out how to find the complex zeros of the equation:
\n" ); document.write( "f(x)=4x^3+19x^2-61x+14
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Algebra.Com's Answer #231018 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Since there are three roots and complex roots come in pairs, at least one must be real.
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\n" ); document.write( "All three roots are real for this equation.
\n" ); document.write( "Looks like \"x=-7\" and \"x=2\" are roots.
\n" ); document.write( "Verify using the equation.
\n" ); document.write( "I'll do one, you verify the other.
\n" ); document.write( "\"4x%5E3%2B19x%5E2-61x%2B14=4%28-7%29%5E3%2B19%2849%29-61%28-7%29%2B14\"
\n" ); document.write( "\"4x%5E3%2B19x%5E2-61x%2B14=-1372%2B931%2B427%2B14\"
\n" ); document.write( "\"4x%5E3%2B19x%5E2-61x%2B14=0\"
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\n" ); document.write( "Now that you have two factors.
\n" ); document.write( "\"%28x%2B7%29%28x-2%29=x%5E2%2B5x-14\"
\n" ); document.write( "You can use polynomial long division to find the remaining factor.
\n" ); document.write( "\"%284x%5E3%2B19x%5E2-61x%2B14%29%2F%28x%5E2%2B5x-14%29\"
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