document.write( "Question 322673: A pair of dice is rolled. Find the probabilities of the given events.
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document.write( "a. The sum of four.
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document.write( "b. The sum of four, given that the sum is odd.
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document.write( "c. The roll is doubles, given that the sum is four. \n" );
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Algebra.Com's Answer #230995 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability of anything is the number of ways that it can happen that you would consider a success divided by the number of ways it can happen total -- successes and failures.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 36 possible outcomes for rolling a standard pair of 6-sided dice. Dice with different numbers of sides and with different numbering than the standard 1 through 6 have different numbers of outcomes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are three ways to make a 4. 1,3 2,2 and 3,1. Hence, the probability of a four is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since 4 is an even number there is no combination where the sum is 4 and the sum is odd simultaneously. The numerator of the fraction is zero.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There is only one way to roll a 4 with doubles...2 and 2. That's why they call it the \"hard way\" at the Craps table.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |