document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322626>Question 322626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Julia were ten more that two times her present age , she will be four times as old as she was four years ago . How old is she now . <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230960 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this, you need to write it as two different equations and then set them equal to each other.<BR>\n" );
document.write( "First we know that at a future age (we will call this F), Julia will be 10 more than 2 times her present age (we will call this P).  This can be written as:<BR>\n" );
document.write( "F = (2*P) + 10<BR>\n" );
document.write( "Secondly, we know at this future age she will be four times as old as she was four years ago (or present age minus 4):<BR>\n" );
document.write( "F = 4* (P - 4)<BR>\n" );
document.write( "Now since both equations equal F, we can set them equal to each other and solve.<BR>\n" );
document.write( "(2*P)+10 = 4*(P-4) (multiply the right side out)<BR>\n" );
document.write( "2P + 10 = 4P - 16  (now subtract 2P from both sides)<BR>\n" );
document.write( "10 = 2P - 16   (now add 16 to both sides)<BR>\n" );
document.write( "26 = 2P  (divide each side by 2)<BR>\n" );
document.write( "13 = P<BR>\n" );
document.write( "So Julia's present age is 13 years old. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );