document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322620>Question 322620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of angle A is 38 less than its complement. find the measure of angle A<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230951 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The definition of complementary angles is two acute angles that add up to 90 degrees.  Written as a formula:\r<BR>\n" );
document.write( "\n" );
document.write( "A+B = 90 (A= measure of angle A, B=measure of angle B, A and B are complementary)\r<BR>\n" );
document.write( "\n" );
document.write( "We also know that angle A is 38 degrees less than B. So you can also write this as a formula:<BR>\n" );
document.write( "A = B-38\r<BR>\n" );
document.write( "\n" );
document.write( "Now we can combine these formulas by plugging formula two into formula one for A and solving for B:<BR>\n" );
document.write( "A+B = 90<BR>\n" );
document.write( "(B-38) + B = 90<BR>\n" );
document.write( "2B - 38 = 90<BR>\n" );
document.write( "2B = 128<BR>\n" );
document.write( "B = 64<BR>\n" );
document.write( "So the measure of angle B is 64 degrees.  Now plug this into formula two to find A:<BR>\n" );
document.write( "A = B-38<BR>\n" );
document.write( "A = 64-38<BR>\n" );
document.write( "A = 26\r<BR>\n" );
document.write( "\n" );
document.write( "The measure of angle A is 26 degrees. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );