document.write( "Question 322539: the perimeter of a rectangle is 240 inches. the length exceeds the width by 76 inches. find the length and the width \n" ); document.write( "
Algebra.Com's Answer #230911 by QH(50)\"\" \"About 
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Width= X
\n" ); document.write( "Length= X+76
\n" ); document.write( "Perimeter= 240\r
\n" ); document.write( "\n" ); document.write( "P=2L+2W
\n" ); document.write( "240=2(x+76)+2(x)
\n" ); document.write( "240=4x+152
\n" ); document.write( "240-152=4x
\n" ); document.write( "88/4=x
\n" ); document.write( "(X)=22(Width)
\n" ); document.write( "(X+76)=98 (Length)\r
\n" ); document.write( "\n" ); document.write( "*check*
\n" ); document.write( "240=2(98)+2(22)
\n" ); document.write( "240=196+44
\n" ); document.write( "240=240
\n" ); document.write( "
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