document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322510>Question 322510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the owner of candy store mixed some peanuts worth $3per pound some cashews worth $9 per pound and some brazil nuts worth $9 per pound to get 50 pounds of a mixture that would sell for $6 per pounds she used 15 fewer pounds of cashews than peanuts how many pounds of each did she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230909 by </B><A HREF=/tutors/aboutme.mpl?userid=QH><B>QH(50)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=QH><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=QH><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First assign variables for each nut. Since it is only asking for the pounds of each, the costs are irrelevant.\r<BR>\n" );
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document.write( "Peanuts= x<BR>\n" );
document.write( "Cashews= x-15<BR>\n" );
document.write( "Brazil Nuts= 50-(x+x-15) or 2x-35\r<BR>\n" );
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document.write( "Add all of the \"nuts\" together to equal 50lbs\r<BR>\n" );
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document.write( "(x)+(x-15)+(2x-35)=50<BR>\n" );
document.write( "4x-50=50<BR>\n" );
document.write( "4x=100<BR>\n" );
document.write( "x=100/4\r<BR>\n" );
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document.write( "(peanuts)     x=25 lbs<BR>\n" );
document.write( "(cashews)  x-15=10 lbs<BR>\n" );
document.write( "Brazils)  2x-35=15 lbs\r<BR>\n" );
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document.write( "check: 20+10+15=50<BR>\n" );
document.write( "             50=50 </SPAN>\n" );
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