document.write( "Question 322522: question:\r
\n" ); document.write( "\n" ); document.write( "an executive committee consisted of ten members: four women and six men. Three members were selected at random to be sent to a metting in Hawaii. A blindfolded woman drew three of the ten names from a hat. All three names drawn were's women's. What was the probability of such luck?
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Algebra.Com's Answer #230896 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The probability of successes in trials where is the probability of success on any given trial is given by:\r
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\n" ); document.write( "\n" ); document.write( "Where is the number of combinations of things taken at a time and is calculated by \r
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\n" ); document.write( "\n" ); document.write( "Here you need 3 successes in 3 trials where the probability of success is 0.4 (4 out of 10 names were women)\r
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\n" ); document.write( "\n" ); document.write( "The arithmetic is yours to do. Hint:\r
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