document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322505>Question 322505</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three intergers is 48.if the first interger is doubled.the sum is 60 if the second interger is doubled the sum is 63 find the integers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230895 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of three intergers is 48. if the first interger is doubled.the sum is 60 if the second interger is doubled the sum is 63 find the integers<BR>\n" );
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document.write( "Doubling the 1st one adds 12, so it's 12 (60-48).<BR>\n" );
document.write( "Doubling the 2nd one adds 15, so it's 15.<BR>\n" );
document.write( "The 3rd one is 21.<BR>\n" );
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document.write( "find the integers<BR>\n" );
document.write( "Stick with integers.  There's no interger.<BR>\n" );
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