document.write( "Question 37442: Vern invested $11,000. Part was invested at 15% and part at 13%. If the total interest at the end of the year is $1,610, how much did he invest at 15%? \n" ); document.write( "
Algebra.Com's Answer #23087 by wuwei96815(245)![]() ![]() ![]() You can put this solution on YOUR website! Let x = the part invested at 13% and $11,000-x = the part invested at 15%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then: \n" ); document.write( "13%x + 15%($11,000-x) = $1,610 \n" ); document.write( "0.13x + 0.15(11,000-x) = 1,610 \n" ); document.write( "0.13x + 1,650 -0.15x = 1,610 \n" ); document.write( "-0.02x = -40 \n" ); document.write( "x = $2,000 \n" ); document.write( "$11,000 -x = $9,000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The answer is that $2,000 was invested at 13% and $9,000 was invested at 15%. \n" ); document.write( " \n" ); document.write( " |