document.write( "Question 37442: Vern invested $11,000. Part was invested at 15% and part at 13%. If the total interest at the end of the year is $1,610, how much did he invest at 15%? \n" ); document.write( "
Algebra.Com's Answer #23087 by wuwei96815(245)\"\" \"About 
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Let x = the part invested at 13% and $11,000-x = the part invested at 15%.\r
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\n" ); document.write( "\n" ); document.write( "Then:
\n" ); document.write( "13%x + 15%($11,000-x) = $1,610
\n" ); document.write( "0.13x + 0.15(11,000-x) = 1,610
\n" ); document.write( "0.13x + 1,650 -0.15x = 1,610
\n" ); document.write( "-0.02x = -40
\n" ); document.write( "x = $2,000
\n" ); document.write( "$11,000 -x = $9,000\r
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\n" ); document.write( "\n" ); document.write( "The answer is that $2,000 was invested at 13% and $9,000 was invested at 15%.
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