document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37315>Question 37315</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Laura invested $2000.  Some at 8% per year and the rest at 10% giving her a total income of $176 per year.  How much money did she invest at 8%.\r<BR>\n" );
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document.write( "I know that I need to create a table.  I'm stuck as to what to do next.  I appreciate your help and thanks so much!<BR>\n" );
document.write( "	Amount invested x Rate = Interest		<BR>\n" );
document.write( "Investment A	2000	7%	.07(2000)<BR>\n" );
document.write( "Investment B			<BR>\n" );
document.write( "Total Investment			176<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23086 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23086\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .08X+.1(2000-X)=176 OR .08X+200-.1X=176 OR -.02X=-24 OR X=24/.02 OR X=1200 THUS 1200 WAS INVESTED @ 8% WHILE 2000-1200=800 INVESTED @ 10%<BR>\n" );
document.write( "PROOF.08*1200+.1*800=176 OR 96+80=176 OR 176=176\r<BR>\n" );
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document.write( "INVESTMENT A    1200@8%=$96 <BR>\n" );
document.write( "INVESTMENT B    800*10%=$80 <BR>\n" );
document.write( "TOTAL INVESTMENT         $176 </SPAN>\n" );
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