document.write( "Question 37302This question is from textbook Elementary and intermediate Algebra
\n" ); document.write( ": please help me with the substitution method.\r
\n" ); document.write( "\n" ); document.write( "3(y-1)=2(x-3)
\n" ); document.write( "3y-2x=-3
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\n" ); document.write( "y=3x
\n" ); document.write( "y=3x+1
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Algebra.Com's Answer #23080 by checkley71(8403)\"\" \"About 
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3(Y-1)=2(X-3) OR 3Y=2X-6 OR Y=(2X-6)/2 SUB (2X-6)/2 FOR Y IN EQUATION #2 WE GET\r
\n" ); document.write( "\n" ); document.write( "3(2X-6)/2-2X=-3 OR (6X-18)/2-2X=-3 OR 3X-9-2X=-3 OR X=6 THWN Y=(2*6-6)/2 OR\r
\n" ); document.write( "\n" ); document.write( "Y=(12-6)/2 OR Y=6/2 OR Y=3\r
\n" ); document.write( "\n" ); document.write( "Y=3X SUB IN EQUATION #2 WE GET 3X=3X+1 3X-3X=1 0=1 NO SOLUTIONS\r
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