document.write( "Question 322320: the length of a rectangle is 6m longer than its width. what are the possible widths if the area is at least 630 cm^2 \n" ); document.write( "
Algebra.Com's Answer #230785 by Fombitz(32388)\"\" \"About 
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For a rectangle,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "In this case,
\n" ); document.write( "\"L%2AW%3E=630\"
\n" ); document.write( "and
\n" ); document.write( "\"L=6%2BW\"
\n" ); document.write( "\"%286%2BW%29W%3E=630\"
\n" ); document.write( "\"W%5E2%2B6W%2B9-630%3E=9\"
\n" ); document.write( "\"%28W%2B3%29%5E2%3E=639\"
\n" ); document.write( "\"W%2B3%3E=sqrt%28639%29\"
\n" ); document.write( "\"W%3E=sqrt%28639%29-3\"
\n" ); document.write( "or approximately,
\n" ); document.write( "\"W%3E=22.278\" cm
\n" ); document.write( "Then
\n" ); document.write( "\"L%3E=28.278\" cm
\n" ); document.write( "and the area,
\n" ); document.write( "\"A%3E=630\"
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