document.write( "Question 322321: A rectangle is inscribed inside the semi-circle y=square root of 100-x^2. what are the dimensions of the rectangle with maximum area? include a diagram \n" ); document.write( "
Algebra.Com's Answer #230778 by Fombitz(32388)\"\" \"About 
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For a rectangle,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "In this case, \"L=2x\" and \"W=y\"
\n" ); document.write( "\"A=2xy\"
\n" ); document.write( "\"y=sqrt%28100-x%5E2%29\"
\n" ); document.write( "\"A=2x%2Asqrt%28100-x%5E2%29\"
\n" ); document.write( "Now area is only a function of x.
\n" ); document.write( "Differentiate with respect to x to find the maximum.
\n" ); document.write( "\"dA%2Fdx=2x%2A%281%2F2%29%28100-x%5E2%29%5E%28-1%2F2%29%28-2x%29%2Bsqrt%28100-x%5E2%29%282%29\"
\n" ); document.write( "\"dA%2Fdx=2sqrt%28100-x%5E2%29-2x%5E2%2Fsqrt%28100-x%5E2%29\"
\n" ); document.write( "Set the derivative equal to zero.
\n" ); document.write( "\"2sqrt%28100-x%5E2%29-2x%5E2%2Fsqrt%28100-x%5E2%29=0\"
\n" ); document.write( "\"2sqrt%28100-x%5E2%29=2x%5E2%2Fsqrt%28100-x%5E2%29\"
\n" ); document.write( "\"100-x%5E2=x%5E2\"
\n" ); document.write( "\"2x%5E2=100\"
\n" ); document.write( "\"x%5E2=50\"
\n" ); document.write( "\"x=sqrt%2850%29=5sqrt%282%29\"
\n" ); document.write( "\"y=sqrt%28100-50%29=5sqrt%282%29\"
\n" ); document.write( "\"A=2%285sqrt%282%29%29%2A5sqrt%282%29\"
\n" ); document.write( "\"A=100\"
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