document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37396>Question 37396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is there a formula that could be used to  explain how you add consecutive numbers  to make multiples of 100.eg.18+19=19=20=21=22=100          38+39+40+41+42=200 that would be suitable for a twelve year old to be able to solve such problems? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23072 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23072\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF YOU DIVIDE 100 BY ANY ODD NUMBER (3,5,7,9,11,13,15,ETC) THAT GIVES YOU A WHOLE NUMBER (IE 100/5=20) THIS TELLS YOU THAT 5 SEQUENTIAL NUMBERS WITH 20 BEING THE MIDDLE NUMBER IS A SOLUTION: THUS 18+19+20+21+22=100\r<BR>\n" );
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document.write( "OR IF YOU DIVIDE 2600 BY  900/15=60 THUS 15 CONSECUTIVE NUMBERS WITH 60 AS THE \r<BR>\n" );
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document.write( "MIDDLE NUMBER WILL ADD UP TO 900 THUS \r<BR>\n" );
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document.write( "53+54+55+56+57+58+59+60+61+62+63+64+65+66+67=900 \r<BR>\n" );
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document.write( "HOPE THIS HELPS. IT'S NOT VERY SIMPLE BUT IT DOES WORK.\r<BR>\n" );
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document.write( "TRY IT WITH 400/25=16 OR 25 NUMBERS WITH 16 AS THE MIDDLE NUMBER\r<BR>\n" );
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document.write( "TRY IT WITH 2200/11=200 OR 11 NUMBERS WIT 200 AS THE MIDDLE NUMBER   </SPAN>\n" );
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