document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322265>Question 322265</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a 22 inch rope is to be cut into two pieces so that one piece is 3 inches longer than twice the other, how long is each piece? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230681 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one piece be x<BR>\n" );
document.write( "the other will be 2x+3<BR>\n" );
document.write( "Length of rope = 22 in<BR>\n" );
document.write( "the sum of the pieces = 22<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+2x+3=22<BR>\n" );
document.write( "3x+3=22<BR>\n" );
document.write( "3x=19<BR>\n" );
document.write( "x=19/3<BR>\n" );
document.write( "x=6.33 in one part<BR>\n" );
document.write( "..<BR>\n" );
document.write( "the other will be 2x+3<BR>\n" );
document.write( "=2*19/3 +3<BR>\n" );
document.write( "=38/3 +3<BR>\n" );
document.write( "=47/3 inches<BR>\n" );
document.write( "..<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "47/3 + 19/3 = 66/3 =22 in<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );