document.write( "Question 322255: Hi;
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document.write( "Can you help me with this problem?\r
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document.write( "Solve the inequality for 5x+7>or= 4/3x - 1. \r
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document.write( "Thank you for your help!
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Algebra.Com's Answer #230677 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 5x+7 >or= (4/3)x - 1 \n" ); document.write( "--- \n" ); document.write( "Subtract (4/3)x from both sides to get: \n" ); document.write( "--- \n" ); document.write( "(11/3)x + 7 >= -1 \n" ); document.write( "--- \n" ); document.write( "Subtract 7 from both sides to get: \n" ); document.write( "(11/3)x >= -8 \n" ); document.write( "--- \n" ); document.write( "Multiply both sides by 3/11 to get: \n" ); document.write( "x >= -24/11 \n" ); document.write( "--- \n" ); document.write( "x >= -2 3/11 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |