document.write( "Question 322255: Hi;
\n" ); document.write( "Can you help me with this problem?\r
\n" ); document.write( "\n" ); document.write( "Solve the inequality for 5x+7>or= 4/3x - 1. \r
\n" ); document.write( "\n" ); document.write( "Thank you for your help!
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Algebra.Com's Answer #230677 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
5x+7 >or= (4/3)x - 1
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\n" ); document.write( "Subtract (4/3)x from both sides to get:
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\n" ); document.write( "(11/3)x + 7 >= -1
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\n" ); document.write( "Subtract 7 from both sides to get:
\n" ); document.write( "(11/3)x >= -8
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\n" ); document.write( "Multiply both sides by 3/11 to get:
\n" ); document.write( "x >= -24/11
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\n" ); document.write( "x >= -2 3/11
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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