document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322144>Question 322144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A scientist has two solutions,which she has labeled Solution A and B.<BR>\n" );
document.write( "Each contains salt. She knows that Solution A is 65% SALT and Solution B is 90%<BR>\n" );
document.write( "SALT. She wants to obtain 120 ounces of a mixture that is 85% salt.\r<BR>\n" );
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document.write( "How many ounces of EACH solution should she use?\r<BR>\n" );
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document.write( "Solution A: _ ounces\r<BR>\n" );
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document.write( "Solution B:_  ounces\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230639 by </B><A HREF=/tutors/aboutme.mpl?userid=galactus><B>galactus(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galactus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=galactus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230639\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A=amount of solution A\r<BR>\n" );
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document.write( ".65A+.90(120-A)=.85(120)\r<BR>\n" );
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document.write( "Solve for A and note that amount of B is 120-A </SPAN>\n" );
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