document.write( "Question 322141: Can someone please help me to sove this. I have tried,and I can not figure out what I am doing wrong. Please help.\r
\n" ); document.write( "\n" ); document.write( "2sqrt(3x^(2)-2)=10 \n" ); document.write( "

Algebra.Com's Answer #230600 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"2sqrt%283x%5E%282%29-2%29=10\"$
\n" ); document.write( " $\"+sqrt%283x%5E%282%29-2%29=5\"$ <--- Divide both sides by 2
\n" ); document.write( " $\"+3x%5E2-2=25\"$ <--- Square both sides
\n" ); document.write( " $\"+3x%5E2=27\"$ <--- Add 2 to both sides
\n" ); document.write( " $\"+x%5E2=9\"$ <--- Divide both sides by 3
\n" ); document.write( " $\"+x=0+%2B-+3\"$ <--- Square root of both sides \n" ); document.write( "

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