document.write( "Question 322081: Find the equation of the line with slope -1 that is the tangent to the curve
\n" ); document.write( "y= 1/(x-1). (5 marks: 1 mark each for a graph, for the general equation of the line, for getting the quadratic, for solving for k, and for the solution).\r
\n" ); document.write( "\n" ); document.write( "I would really appreciate if someone could solve it for me.
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Algebra.Com's Answer #230597 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
A line with a slope of -1 would have a slope-intercept form of,
\n" ); document.write( "\"y=mx%2Bb\"
\n" ); document.write( "\"y=-x%2Bb\"
\n" ); document.write( "Since \"y=1%2F%28x-1%29\", then solve for \"b\" using \"x=0\",
\n" ); document.write( "\"-0%2Bb=1%2F%280-1%29\"
\n" ); document.write( "\"b=1%2F-1=-1\"
\n" ); document.write( "\"highlight%28y=-x-1%29\"
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\n" ); document.write( "\"graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C1%2F%28x-1%29%2C-x-1%29\"
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\n" ); document.write( "As you can see from graphing the equations, that only solves for one line.
\n" ); document.write( "You can use a symmetry argument to find the other line, \"y=-x%2Bb2\", since the perpendicular line, \"y=x-1\" is perpendicular to both and intersects at both intersection points.
\n" ); document.write( "\"graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C1%2F%28x-1%29%2C-x-1%2Cx-1%29\"
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\n" ); document.write( "\"x-1=1%2F%28x-1%29\"
\n" ); document.write( "\"%28x-1%29%5E2=1\"
\n" ); document.write( "\"x-1=0+%2B-+1\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"x=2\" and \"x=0\"
\n" ); document.write( "When \"x=2\", then
\n" ); document.write( "\"-2%2Bb=1%2F%282-1%29\"
\n" ); document.write( "\"b=3\"
\n" ); document.write( "The other line is then,
\n" ); document.write( "\"highlight_green%28y=-x%2B3%29\"
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\n" ); document.write( "\"graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C1%2F%28x-1%29%2C-x-1%2Cx-1%2C-x%2B3%29\"
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\n" ); document.write( "What's k?
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