document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=322099>Question 322099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> form a point 100 meter above the ground ,the angle of depression of the two objects  due south on the ground are 60° and 45° . the distance between the object is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230569 by </B><A HREF=/tutors/aboutme.mpl?userid=galactus><B>galactus(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galactus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=galactus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230569\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose you were standing on the 'cliff' 100 meters above the ground and looking striaght ahead toward the horizon, then you looked down 45 degrees. That is the angle of depression.\r<BR>\n" );
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document.write( "So, this is just the law of tangents.\r<BR>\n" );
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document.write( "100tan(45)-100cot(60)=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100-100sqrt%283%29%2F3 ALIGN=MIDDLE  ALT=\"100-100sqrt%283%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >=42.265 meters apart\r<BR>\n" );
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document.write( "or, another way\r<BR>\n" );
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document.write( "100tan(45)-100tan(30)=42.265 meters apart. </SPAN>\n" );
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