document.write( "Question 322072: x^2 + 10x = 300
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document.write( "Find the positive value for x.
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document.write( "Give your answer correct to 3 significant figures. \n" );
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Algebra.Com's Answer #230564 by Jk22(389)![]() ![]() You can put this solution on YOUR website! x^2+10x-300=0\r \n" ); document.write( "\n" ); document.write( "x=(-10+sqrt(100+1200))/2=-5+5*sqrt(13)=5(-1+sqrt(13)) (+ to get a positive ans)\r \n" ); document.write( "\n" ); document.write( "Square root of 13 can be extracted manually :\r \n" ); document.write( "\n" ); document.write( "13...|3,605 \n" ); document.write( "9----| \n" ); document.write( "------------ \n" ); document.write( "40.0.|66x6=396 \n" ); document.write( "396..| \n" ); document.write( "------------ \n" ); document.write( "40.0.|680x0 \n" ); document.write( "40000|6805x5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "hence : x=5*2,605~13,025 \n" ); document.write( " |