document.write( "Question 322033: The area of a rectangle is 45 square cm. If the length is 4 cm greater than the width, what are the dimension of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #230539 by Jk22(389)\"\" \"About 
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let w the width : w(w+4)=45=>w^2+4w+45=0\r
\n" ); document.write( "\n" ); document.write( "=>w=(-4+-sqrt(196))/2=5,-9=(-4(+/-)14)/2\r
\n" ); document.write( "\n" ); document.write( "-9 is nonsense, so width=5cm, length=4+5=9cm (5cm*9cm=45cm^2)
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