document.write( "Question 322033: The area of a rectangle is 45 square cm. If the length is 4 cm greater than the width, what are the dimension of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #230539 by Jk22(389)![]() ![]() You can put this solution on YOUR website! let w the width : w(w+4)=45=>w^2+4w+45=0\r \n" ); document.write( "\n" ); document.write( "=>w=(-4+-sqrt(196))/2=5,-9=(-4(+/-)14)/2\r \n" ); document.write( "\n" ); document.write( "-9 is nonsense, so width=5cm, length=4+5=9cm (5cm*9cm=45cm^2) \n" ); document.write( " |