document.write( "Question 321922: Bob is driving west bound and passes Joe driving eastbound at 50mph. How fast will Bob have to drive if he turns around and catches Joe 1/2 mile down the road from where they first passed each other? \n" ); document.write( "
Algebra.Com's Answer #230533 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The assumption is that Bob stops immediately as they pass each other and turns around using no time.
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\n" ); document.write( "For constant speed or rate,
\n" ); document.write( "Rate*Time=Distance
\n" ); document.write( "\"R%2At=D\"
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\n" ); document.write( "For Joe traveling at 50 mph and meeting Bob in 1/2 mile,
\n" ); document.write( "\"50%2At=1%2F2\"
\n" ); document.write( "\"t=1%2F100\" hour
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\n" ); document.write( "Since Bob starts at zero speed, the distance equation is slightly different than for Joe who's traveling at constant speed.
\n" ); document.write( "\"a=%28vf-vi%29%2Ft\" where a=acceleration, vf=Bob's final speed, vi=Bob's initial speed, t=time.
\n" ); document.write( "and also,
\n" ); document.write( "\"D=%281%2F2%29at%5E2\"
\n" ); document.write( "\"D=%281%2F2%29%28%28vf-vi%29%2Ft%29%2At%5E2\"
\n" ); document.write( "\"D=%281%2F2%29%28vf-vi%29%2At\"
\n" ); document.write( "\"1%2F2=%281%2F2%29%28vf-0%29%2A%281%2F100%29\"
\n" ); document.write( "\"vf=100\" mph
\n" ); document.write( "Bob will be traveling at 100 mph when they meet.
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