document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37294>Question 37294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x:<BR>\n" );
document.write( "1) 3^x=729  I got 6<BR>\n" );
document.write( "2) 6^x-28=-8  I got 10/3<BR>\n" );
document.write( "3) 4ln 3x =15  I got 14.17\r<BR>\n" );
document.write( "\n" );
document.write( "am I correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23053 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, let's see...<BR>\n" );
document.write( "1) 3^x = 729  I got 6  ====> CORRECT<BR>\n" );
document.write( "2) 6^x - 28 = -8  I got 10/3   ====> not correct.  First add 28 to both sides...<BR>\n" );
document.write( "6^x = 20  <BR>\n" );
document.write( "Now take the log of both sides and solve for x...<BR>\n" );
document.write( "ln 6^x = ln 20<BR>\n" );
document.write( "x = ln 20 / ln 6 and<BR>\n" );
document.write( "x = 1.672<BR>\n" );
document.write( "3) 4ln 3x =15  I got 14.17 ====> CORRECT.  Here divide by four, then exponentiate and solve and we get<BR>\n" );
document.write( "ln 3x = 15/4<BR>\n" );
document.write( "3x = e^(15/4)<BR>\n" );
document.write( "x = e^(15/4) / 3<BR>\n" );
document.write( "x = 14.17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );