document.write( "Question 322013: The width of a rectangle is 6 feet, and the diagonal is 10 feet. What is the area of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #230494 by nyc_function(2741) $\"\"$ $\"About$

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Length = 6\r
\n" ); document.write( "\n" ); document.write( "diagnoal = 10\r
\n" ); document.write( "\n" ); document.write( "side = x\r
\n" ); document.write( "\n" ); document.write( "We need to find x using the Pythagorean Theorem.\r
\n" ); document.write( "\n" ); document.write( "x^2 + 6^2 = 10^2\r
\n" ); document.write( "\n" ); document.write( "x^2 + 36 = 100\r
\n" ); document.write( "\n" ); document.write( "x^2 = 100 - 36\r
\n" ); document.write( "\n" ); document.write( "x^2 = 64\r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%28x%5E2%29\"$ = $\"sqrt%2864%29\"$ \r
\n" ); document.write( "\n" ); document.write( "x = 8\r
\n" ); document.write( "\n" ); document.write( "The width is 8.\r
\n" ); document.write( "\n" ); document.write( "Area = length times width\r
\n" ); document.write( "\n" ); document.write( "Area = length times width\r
\n" ); document.write( "\n" ); document.write( "Area = 6 times 8\r
\n" ); document.write( "\n" ); document.write( "Area = 48 square feet\r
\n" ); document.write( "\n" ); document.write( "Done! \n" ); document.write( "

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