document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37405>Question 37405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x-2y=2<BR>\n" );
document.write( "2x+3y=11\r<BR>\n" );
document.write( "\n" );
document.write( "use substitution method to solve system<BR>\n" );
document.write( "if dependant or inconsistant please indicate </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23049 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From<BR>\n" );
document.write( "x - 2 y = 2<BR>\n" );
document.write( "2x + 3y = 11<BR>\n" );
document.write( "Solve for x in the first and substitute into the second:<BR>\n" );
document.write( "x = 2y + 2<BR>\n" );
document.write( "2(2y + 2) + 3y = 11<BR>\n" );
document.write( "4y + 4 + 3y = 11<BR>\n" );
document.write( "7y + 4 = 11<BR>\n" );
document.write( "7y = 7<BR>\n" );
document.write( "y = 1<BR>\n" );
document.write( "Then since x = 2y + 2, we have<BR>\n" );
document.write( "x = 2(1) + 2 <BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "Our solution is (4, 1) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );