document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321959>Question 321959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Roger is 6 years older than Zoe. Three years ago, Zoe's age was two-thirds of Roger's age. Find their present ages.\r<BR>\n" );
document.write( "\n" );
document.write( "*Let Roger's age be x and Zoe's age be y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230474 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Zoe's age be x<BR>\n" );
document.write( "Roger will be x+6<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3  years ago<BR>\n" );
document.write( "Zoe was x-3<BR>\n" );
document.write( "Roger was x+6-3=x+3 years<BR>\n" );
document.write( "x-3 = 2/3 * x+3<BR>\n" );
document.write( "3(x-3)=2(x+3)<BR>\n" );
document.write( "3x-9=2x+6<BR>\n" );
document.write( "x=15  that is Zoes's age<BR>\n" );
document.write( "Roger is 15+6 = 21 years </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );