document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321965>Question 321965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man invests $2,200 in three accounts that pay 6%, 8%, 9% in annual interest, respectively. he has three times as much invented at 9% as he does at 6%. if his total interest for year is $178, how much is invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230473 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6% --- amount x<BR>\n" );
document.write( "9%---- amount 3x<BR>\n" );
document.write( "8% --- amount 2200- (3x+x)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Interest recieved = 178<BR>\n" );
document.write( "..<BR>\n" );
document.write( "0.06x+0.09*3x+0.08(2200-4x)=178<BR>\n" );
document.write( "0.06x+0.27x+176.00-0.32x=178<BR>\n" );
document.write( "0.01x=2<BR>\n" );
document.write( "x=200 at6%<BR>\n" );
document.write( "3x= 600 at9%<BR>\n" );
document.write( "2200-4x= 2200-800=1400 at 8% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );