document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321939>Question 321939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The supplement of an angle measures 40° more than twice its complement. Find the measure of the angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230460 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the measure of angle be x<BR>\n" );
document.write( "complement will be 90-x<BR>\n" );
document.write( "40 more than twice its complement<BR>\n" );
document.write( "= 2(90-x)+40<BR>\n" );
document.write( "..<BR>\n" );
document.write( "180-x is the supplement<BR>\n" );
document.write( "180-x = 2(90-x)+40<BR>\n" );
document.write( "180-x=180-2x+40<BR>\n" );
document.write( "2x-x=40<BR>\n" );
document.write( "x=40 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );