document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37398>Question 37398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2a=3b-13<BR>\n" );
document.write( "b=2a+7\r<BR>\n" );
document.write( "\n" );
document.write( "Use substitution method to solve system .<BR>\n" );
document.write( "If system is dependant or inconsistant so indicate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23044 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From<BR>\n" );
document.write( "2a = 3b - 13<BR>\n" );
document.write( "b = 2a + 7<BR>\n" );
document.write( "let us take the given value for b in the second equation and substitute it into the first equation, like this<BR>\n" );
document.write( "2a = 3(2a + 7) - 13<BR>\n" );
document.write( "2a = 6a + 21 - 13<BR>\n" );
document.write( "2a = 6a + 8<BR>\n" );
document.write( "-4a = 8<BR>\n" );
document.write( "a = -2<BR>\n" );
document.write( "Now using b = 2a + 7 we have<BR>\n" );
document.write( "b = 2(-2) + 7<BR>\n" );
document.write( "b = -4 + 7 = 3<BR>\n" );
document.write( "So our solution is (-2, 3) and is a consistent system. </SPAN>\n" );
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