document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37395>Question 37395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> r+3s=9<BR>\n" );
document.write( "3r+2s=13\r<BR>\n" );
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document.write( "Use substitution method to solve system.<BR>\n" );
document.write( "If its dependant or inconsistant, so indicate </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23042 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from<BR>\n" );
document.write( "r + 3s = 9<BR>\n" );
document.write( "3r + 2s = 13<BR>\n" );
document.write( "we solve the first equation for r and substitute it into the second equation:<BR>\n" );
document.write( "r = -3s + 9<BR>\n" );
document.write( "3(-3s + 9) + 2s = 13<BR>\n" );
document.write( "-9s + 27 + 2s = 13<BR>\n" );
document.write( "-7s = -14<BR>\n" );
document.write( "s = 2<BR>\n" );
document.write( "Then since r = -3s + 9, we have<BR>\n" );
document.write( "r = -3(2) + 9 = 3<BR>\n" );
document.write( "Our solution is then (3, 2), a consistent system. </SPAN>\n" );
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