document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321827>Question 321827</A>: <I><SPAN STYLE=\"word-break: break-all;\"> c + 2/3 = 5. this is the problem im trying to solve. as i understand it c + 2/3 -2/3 = 5 - 2/3. then what?? thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230406 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c + 2/3 = 5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "5 is equvalent to 15/3.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Make your equation:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c + 2/3 = 15/3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Substract 2/3 from  both sides of the equation to get:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = 15/3 - 2/3 which becomes:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = 13/3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "That's your answer.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "To confirm, let c = 13/3 and your original equation becomes:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "13/3 + 2/3 = 15/3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Combine like terms to get:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "15/3 = 15/3 which is true confirming the fact the c = 2/3 is a good answer.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The reason I made 5 = 15/3 is because the denominator are then equal which allows you to subtract one from the other.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "You would have had to eventually make the fractions with the same denominator or convert all to decimals anyway.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c + 2/3 = 5 becomes c + .6666666667 = 5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Subtract .6666666667 from both sides of the equation to get:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = 4.333333333333 which is equivalent to 4 and 1/3 which is equivalent to 13/3.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );