document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321779>Question 321779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x+a=(b/3)x and b=/ 3, then x =?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230380 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If x+a=(b/3)x and b is not = 3, then x =?<BR>\n" );
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document.write( "x - (b/3)x = -a<BR>\n" );
document.write( "x(1-(b/3)) = -a<BR>\n" );
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document.write( "x = -a/[1-(b/3)]<BR>\n" );
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document.write( "x = -a/[(3-b)/3]<BR>\n" );
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document.write( "x = -3a/(3-b)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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